The Cut Loci, Conjugate Loci and Poles in a Complete Riemannian ManifoldGeometric and Functional Analysis - Tập 22 - Trang 1400-1406 - 2012
Nobuhiro Innami, Katsuhiro Shiohama, Toshiro Soga
Let M be a complete Riemannian manifold. We first prove that there exist at least two geodesics connecting p and every point in M if the tangent cut locus of
$${p \in M}$$
is not empty and does not meet its tangent conjugate locus. It follows from this that if M admits a pole and
...... hiện toàn bộ
Flattening a non-degenerate CR singular point of real codimension twoGeometric and Functional Analysis - Tập 28 - Trang 289-333 - 2018
Hanlong Fang, Xiaojun Huang
This paper continues the previous studies in two papers of Huang–Yin [HY16,HY17] on the flattening problem of a CR singular point of real codimension two sitting in a submanifold in
$${{\mathbb {C}}^{n+1}}$$
with n + 1 ≥ 3, whose CR points are no...... hiện toàn bộ
An isoperimetric inequality for the Heisenberg groupsGeometric and Functional Analysis - Tập 8 - Trang 219-233 - 1998
D. Allcock
We show that the Heisenberg groups
$ \cal {H}^{2n+1} $
of dimension five and higher, considered as Riemannian manifolds, satisfy a quadratic isoperimetric inequality. (This means that each loop of length L bounds a disk of area ~ L
2.) This implies several important results about isoperimetric inequalities for discrete groups that act ...... hiện toàn bộ
On the random Chowla conjectureGeometric and Functional Analysis - Tập 33 - Trang 749-777 - 2023
Oleksiy Klurman, Ilya D. Shkredov, Max Wenqiang Xu
We show that for a Steinhaus random multiplicative function
$$f:{\mathbb {N}}\rightarrow {\mathbb {D}}$$
and any polynomial
$$P(x)\in {\mathbb {Z}}[x]$$
of
...... hiện toàn bộ
On the Exceptional Set for Absolute Continuity of Bernoulli ConvolutionsGeometric and Functional Analysis - Tập 24 - Trang 946-958 - 2014
Pablo Shmerkin
We prove that the set of exceptional
$${\lambda\in (1/2,1)}$$
such that the associated Bernoulli convolution is singular has zero Hausdorff dimension, and likewise for biased Bernoulli convolutions, with the exceptional set independent of the bia...... hiện toàn bộ
Finitary random interlacements and the Gaboriau–Lyons problemGeometric and Functional Analysis - Tập 29 - Trang 659-689 - 2019
Lewis Bowen
The von Neumann–Day problem asks whether every non-amenable group contains a non-abelian free group. It was answered in the negative by Ol’shanskii in the 1980s. The measurable version (formulated by Gaboriau–Lyons) asks whether every non-amenable measured equivalence relation contains a non-amenable treeable subequivalence relation. This paper obtains a positive answer in the case of arbitrary Be...... hiện toàn bộ