On judicious partitions of graphs
Tóm tắt
Let
$$k, m$$
be positive integers, let
$$G$$
be a graph with
$$m$$
edges, and let
$$h(m)=\sqrt{2m+\frac{1}{4}}-\frac{1}{2}$$
. Bollobás and Scott asked whether
$$G$$
admits a
$$k$$
-partition
$$V_{1}, V_{2}, \ldots , V_{k}$$
such that
$$\max _{1\le i\le k} \{e(V_{i})\}\le \frac{m}{k^2}+\frac{k-1}{2k^2}h(m)$$
and
$$e(V_1, \ldots , V_k)\ge {k-1\over k} m +{k-1\over 2k}h(m) -\frac{(k-2)^{2}}{8k}$$
. In this paper, we present a positive answer to this problem on the graphs with large number of edges and small number of vertices with degrees being multiples of
$$k$$
. Particularly, if
$$d$$
is not a multiple of
$$k$$
and
$$G$$
is
$$d$$
-regular with
$$m\ge {9\over 128}k^4(k-2)^2$$
, then
$$G$$
admits a
$$k$$
-partition as desired. We also improve an earlier result by showing that
$$G$$
admits a partition
$$V_{1}, V_{2}, \ldots , V_{k}$$
such that
$$e(V_{1},V_{2},\ldots ,V_{k})\ge \frac{k-1}{k}m+\frac{k-1}{2k}h(m)-\frac{(k-2)^{2}}{2(k-1)}$$
and
$$\max _{1\le i\le k}\{e(V_{i})\}\le \frac{m}{k^{2}}+\frac{k-1}{2k^{2}}h(m)$$
.
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